The converse of the statement "If $p < q$,then $p - x < q - x$" is -

If $p \to (q \lor \sim r)$ is false, then the truth values of $(p \leftrightarrow q) \land r$ and $\sim p \to \sim q$ are :

If $\sim p \vee q$ is false, then which of the following is correct?

The statement pattern $\sim(p \vee q) \vee(\sim p \wedge q)$ is equivalent to

The contrapositive of the inverse of $p$ $\rightarrow (p$ $\rightarrow q)$ is

Consider the following statements:
$p$: the switch $S_1$ is closed.
$q$: the switch $S_2$ is closed.
$r$: the switch $S_3$ is closed.
Then the switching circuit represented by the statement $(p \wedge q) \vee (\sim p \wedge (\sim q \vee p \vee r))$ is